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5/8g-6=1/4g.g
We move all terms to the left:
5/8g-6-(1/4g.g)=0
Domain of the equation: 8g!=0
g!=0/8
g!=0
g∈R
Domain of the equation: 4g.g)!=0We add all the numbers together, and all the variables
g!=0/1
g!=0
g∈R
5/8g-(+1/4g.g)-6=0
We get rid of parentheses
5/8g-1/4g.g-6=0
We calculate fractions
20g/32g^2+(-8g)/32g^2-6=0
We multiply all the terms by the denominator
20g+(-8g)-6*32g^2=0
Wy multiply elements
-192g^2+20g+(-8g)=0
We get rid of parentheses
-192g^2+20g-8g=0
We add all the numbers together, and all the variables
-192g^2+12g=0
a = -192; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-192)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-192}=\frac{-24}{-384} =1/16 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-192}=\frac{0}{-384} =0 $
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