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5/8+1/4x=1/2x
We move all terms to the left:
5/8+1/4x-(1/2x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/4x-(+1/2x)+5/8=0
We get rid of parentheses
1/4x-1/2x+5/8=0
We calculate fractions
80x^2/512x^2+128x/512x^2+(-256x)/512x^2=0
We multiply all the terms by the denominator
80x^2+128x+(-256x)=0
We get rid of parentheses
80x^2+128x-256x=0
We add all the numbers together, and all the variables
80x^2-128x=0
a = 80; b = -128; c = 0;
Δ = b2-4ac
Δ = -1282-4·80·0
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16384}=128$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-128)-128}{2*80}=\frac{0}{160} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-128)+128}{2*80}=\frac{256}{160} =1+3/5 $
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