5/8(y-24)=1/4(y+12)

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Solution for 5/8(y-24)=1/4(y+12) equation: 



5/8(y-24)=1/4(y+12)

We move all terms to the left:

5/8(y-24)-(1/4(y+12))=0



Domain of the equation: 8(y-24)!=0

y∈R





Domain of the equation: 4(y+12))!=0

y∈R



We calculate fractions


(20yy/(8(y-24)*4(y+12)))+(-8yy/(8(y-24)*4(y+12)))=0



We calculate terms in parentheses: +(20yy/(8(y-24)*4(y+12))), so:

20yy/(8(y-24)*4(y+12))

We multiply all the terms by the denominator


20yy

Back to the equation:

+(20yy)





We calculate terms in parentheses: +(-8yy/(8(y-24)*4(y+12))), so:

-8yy/(8(y-24)*4(y+12))

We multiply all the terms by the denominator


-8yy

Back to the equation:

+(-8yy)



We get rid of parentheses

20yy-8yy=0

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