# 5/8(y-24)=1/4(y+12)

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## Solution for 5/8(y-24)=1/4(y+12) equation:

5/8(y-24)=1/4(y+12)
We move all terms to the left:
5/8(y-24)-(1/4(y+12))=0

Domain of the equation: 8(y-24)!=0
y∈R

Domain of the equation: 4(y+12))!=0
y∈R

We calculate fractions

(20yy/(8(y-24)*4(y+12)))+(-8yy/(8(y-24)*4(y+12)))=0

We calculate terms in parentheses: +(20yy/(8(y-24)*4(y+12))), so:
20yy/(8(y-24)*4(y+12))
We multiply all the terms by the denominator

20yy
Back to the equation:
+(20yy)

We calculate terms in parentheses: +(-8yy/(8(y-24)*4(y+12))), so:
-8yy/(8(y-24)*4(y+12))
We multiply all the terms by the denominator

-8yy
Back to the equation:
+(-8yy)

We get rid of parentheses
20yy-8yy=0

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