5/7x1/4x+10=9/10x

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Solution for 5/7x1/4x+10=9/10x equation: 


x in (-oo:+oo)

(((5/7)*x^1)/4)*x+10 = (9/10)*x // - (9/10)*x

(((5/7)*x^1)/4)*x-((9/10)*x)+10 = 0

(((5/7)*x)/4)*x+(-9/10)*x+10 = 0

5/28*x^2-9/10*x+10 = 0

DELTA = (-9/10)^2-(5/28*4*10)

DELTA = -4433/700

DELTA < 0

x belongs to the empty set

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