If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5/7x+5/2+1/14x=4/7
We move all terms to the left:
5/7x+5/2+1/14x-(4/7)=0
Domain of the equation: 7x!=0
x!=0/7
x!=0
x∈R
Domain of the equation: 14x!=0We add all the numbers together, and all the variables
x!=0/14
x!=0
x∈R
5/7x+1/14x+5/2-(+4/7)=0
We get rid of parentheses
5/7x+1/14x+5/2-4/7=0
We calculate fractions
3430x^2/2744x^2+280x/2744x^2+196x/2744x^2+(-224x)/2744x^2=0
We multiply all the terms by the denominator
3430x^2+280x+196x+(-224x)=0
We add all the numbers together, and all the variables
3430x^2+476x+(-224x)=0
We get rid of parentheses
3430x^2+476x-224x=0
We add all the numbers together, and all the variables
3430x^2+252x=0
a = 3430; b = 252; c = 0;
Δ = b2-4ac
Δ = 2522-4·3430·0
Δ = 63504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{63504}=252$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(252)-252}{2*3430}=\frac{-504}{6860} =-18/245 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(252)+252}{2*3430}=\frac{0}{6860} =0 $
| (2/x-1)+(9/x)=(-3/x^2-1) | | Y=2x^2-x-8 | | 3(-2x+5)=27 | | 4b^2=-10b-8 | | x-4=9+4 | | 4-2x=5x+7 | | -26+8/9v=-5 | | -6+9x=180 | | 5k^2=-10k-5 | | 7+3m=2m | | x^2-22x-9x^2=0 | | 0.4h-1/7=5 | | 14n-10=-6 | | .050=x(.20)/x | | 12x+5=3x+13 | | 3k^2+8k=19 | | 6u-30=0 | | 4x=4.0 | | 3(2x-4)-8x=74 | | 6n^2=3 | | 2(2x+3)-2x=12 | | 3.14x2.5= | | -1+3x=-4+2x | | V^2=10—3v | | V^2=10–3v | | 5^x+(1/5)^2x-3=0 | | 6=3u-u | | K^2=56+k | | 10(-12x+18)=-1020 | | 18=y+8y | | 4(x+5)-17=-21 | | X²-6x-19=0 |