5/7x+32=67

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Solution for 5/7x+32=67 equation: 



5/7x+32=67

We move all terms to the left:

5/7x+32-(67)=0



Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



We add all the numbers together, and all the variables

5/7x-35=0

We multiply all the terms by the denominator


-35*7x+5=0

Wy multiply elements

-245x+5=0

We move all terms containing x to the left, all other terms to the right

-245x=-5

x=-5/-245

x=1/49

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