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5/7p+2/p=9
We move all terms to the left:
5/7p+2/p-(9)=0
Domain of the equation: 7p!=0
p!=0/7
p!=0
p∈R
Domain of the equation: p!=0We calculate fractions
p∈R
5p/7p^2+14p/7p^2-9=0
We multiply all the terms by the denominator
5p+14p-9*7p^2=0
We add all the numbers together, and all the variables
19p-9*7p^2=0
Wy multiply elements
-63p^2+19p=0
a = -63; b = 19; c = 0;
Δ = b2-4ac
Δ = 192-4·(-63)·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-19}{2*-63}=\frac{-38}{-126} =19/63 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+19}{2*-63}=\frac{0}{-126} =0 $
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