5/7=6(7x+9)/9

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Solution for 5/7=6(7x+9)/9 equation: 



5/7=6(7x+9)/9

We move all terms to the left:

5/7-(6(7x+9)/9)=0

We calculate fractions


(-(6(7x+9)*7)/()+()/()=0



We calculate terms in parentheses: +(-(6(7x+9)*7)/()+()/(), so:

-(6(7x+9)*7)/()+()/(

We add all the numbers together, and all the variables

-(6(7x+9)*7)/()+1

We multiply all the terms by the denominator


-(6(7x+9)*7)+1*()



We calculate terms in parentheses: -(6(7x+9)*7), so:

6(7x+9)*7

We multiply parentheses

294x+378

Back to the equation:

-(294x+378)



We add all the numbers together, and all the variables

-(294x+378)

We get rid of parentheses

-294x-378

Back to the equation:

+(-294x-378)



We get rid of parentheses

-294x-378=0

We move all terms containing x to the left, all other terms to the right

-294x=378

x=378/-294

x=-1+2/7

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