5/7*y=35

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Solution for 5/7*y=35 equation: 



5/7y=35

We move all terms to the left:

5/7y-(35)=0



Domain of the equation: 7y!=0

y!=0/7

y!=0

y∈R



We multiply all the terms by the denominator


-35*7y+5=0

Wy multiply elements

-245y+5=0

We move all terms containing y to the left, all other terms to the right

-245y=-5

y=-5/-245

y=1/49

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