5/7(t+7)=2/7t=23

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Solution for 5/7(t+7)=2/7t=23 equation: 



5/7(t+7)=2/7t=23

We move all terms to the left:

5/7(t+7)-(2/7t)=0



Domain of the equation: 7(t+7)!=0

t∈R





Domain of the equation: 7t)!=0

t!=0/1

t!=0

t∈R



We add all the numbers together, and all the variables

5/7(t+7)-(+2/7t)=0

We get rid of parentheses

5/7(t+7)-2/7t=0

We calculate fractions


35t/(49t^2+343t)+(-14tt/(49t^2+343t)=0



We calculate terms in parentheses: +(-14tt/(49t^2+343t), so:

-14tt/(49t^2+343t

We multiply all the terms by the denominator


-14tt

Back to the equation:

+(-14tt)



We get rid of parentheses

35t/(49t^2+343t)-14tt=0

We multiply all the terms by the denominator


35t-14tt*(49t^2+343t)=0

We multiply parentheses

-686t^3-4802t^2+35t=0

We do not support etpression: t^3

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