5/6z=6-11/12z

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Solution for 5/6z=6-11/12z equation:



5/6z=6-11/12z
We move all terms to the left:
5/6z-(6-11/12z)=0
Domain of the equation: 6z!=0
z!=0/6
z!=0
z∈R
Domain of the equation: 12z)!=0
z!=0/1
z!=0
z∈R
We add all the numbers together, and all the variables
5/6z-(-11/12z+6)=0
We get rid of parentheses
5/6z+11/12z-6=0
We calculate fractions
60z/72z^2+66z/72z^2-6=0
We multiply all the terms by the denominator
60z+66z-6*72z^2=0
We add all the numbers together, and all the variables
126z-6*72z^2=0
Wy multiply elements
-432z^2+126z=0
a = -432; b = 126; c = 0;
Δ = b2-4ac
Δ = 1262-4·(-432)·0
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(126)-126}{2*-432}=\frac{-252}{-864} =7/24 $
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(126)+126}{2*-432}=\frac{0}{-864} =0 $

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