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5/6x-10=1/3(x-15
We move all terms to the left:
5/6x-10-(1/3(x-15)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 3(x-15)-10!=0We calculate fractions
We move all terms containing x to the left, all other terms to the right
3(x-15)!=10
x∈R
(15x(x-10)/(18x^2(x-10)+(-(1*6x)/(18x^2(x-10)=0
We calculate terms in parentheses: +(15x(x-10)/(18x^2(x-10)+(-(1*6x)/(18x^2(x-10), so:
15x(x-10)/(18x^2(x-10)+(-(1*6x)/(18x^2(x-10
We can not solve this equation
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