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5/6x-1/12(4-x)=1/6(x+3)
We move all terms to the left:
5/6x-1/12(4-x)-(1/6(x+3))=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 12(4-x)!=0
x∈R
Domain of the equation: 6(x+3))!=0We add all the numbers together, and all the variables
x∈R
5/6x-1/12(-1x+4)-(1/6(x+3))=0
We calculate fractions
We do not support expression: x^3(
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