5/6x+1=1/4x-3

Solution for 5/6x+1=1/4x-3 equation:

5/6x+1=1/4x-3

We move all terms to the left:

5/6x+1-(1/4x-3)=0


Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R



Domain of the equation: 4x-3)!=0

x∈R


We get rid of parentheses

5/6x-1/4x+3+1=0

We calculate fractions


20x/24x^2+(-6x)/24x^2+3+1=0

We add all the numbers together, and all the variables

20x/24x^2+(-6x)/24x^2+4=0

We multiply all the terms by the denominator


20x+(-6x)+4*24x^2=0

Wy multiply elements

96x^2+20x+(-6x)=0

We get rid of parentheses

96x^2+20x-6x=0

We add all the numbers together, and all the variables

96x^2+14x=0

a = 96; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·96·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*96}=\frac{-28}{192}
=-7/48
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*96}=\frac{0}{192}
=0
$