5/6h-7/12=-3/h-13/6

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Solution for 5/6h-7/12=-3/h-13/6 equation: 


D( h )

h = 0

h = 0

h = 0

h in (-oo:0) U (0:+oo)

(5/6)*h-(7/12) = -3/h-(13/6) // + -3/h-(13/6)

(5/6)*h-(-3/h)-(7/12)+13/6 = 0

(5/6)*h+3*h^-1-7/12+13/6 = 0

5/6*h^1+3*h^-1+19/12*h^0 = 0

(5/6*h^2+19/12*h^1+3*h^0)/(h^1) = 0 // * h^2

h^1*(5/6*h^2+19/12*h^1+3*h^0) = 0

h^1

(5/6)*h^2+(19/12)*h+3 = 0

(5/6)*h^2+(19/12)*h+3 = 0

DELTA = (19/12)^2-(3*4*(5/6))

DELTA = -1079/144

DELTA < 0

h in { } 

h belongs to the empty set

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