5/6b+28=3

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Solution for 5/6b+28=3 equation: 



5/6b+28=3

We move all terms to the left:

5/6b+28-(3)=0



Domain of the equation: 6b!=0

b!=0/6

b!=0

b∈R



We add all the numbers together, and all the variables

5/6b+25=0

We multiply all the terms by the denominator


25*6b+5=0

Wy multiply elements

150b+5=0

We move all terms containing b to the left, all other terms to the right

150b=-5

b=-5/150

b=-1/30

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