5/6(3x-2)=4/3(2x+36)

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Solution for 5/6(3x-2)=4/3(2x+36) equation: 



5/6(3x-2)=4/3(2x+36)

We move all terms to the left:

5/6(3x-2)-(4/3(2x+36))=0



Domain of the equation: 6(3x-2)!=0

x∈R





Domain of the equation: 3(2x+36))!=0

x∈R



We calculate fractions


(15x2/(6(3x-2)*3(2x+36)))+(-24x3/(6(3x-2)*3(2x+36)))=0



We calculate terms in parentheses: +(15x2/(6(3x-2)*3(2x+36))), so:

15x2/(6(3x-2)*3(2x+36))

We multiply all the terms by the denominator


15x2

We add all the numbers together, and all the variables

15x^2

Back to the equation:

+(15x^2)





We calculate terms in parentheses: +(-24x3/(6(3x-2)*3(2x+36))), so:

-24x3/(6(3x-2)*3(2x+36))

We multiply all the terms by the denominator


-24x3

We add all the numbers together, and all the variables

-24x^3

We do not support expression: x^3

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