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5/4y+y=505
We move all terms to the left:
5/4y+y-(505)=0
Domain of the equation: 4y!=0We add all the numbers together, and all the variables
y!=0/4
y!=0
y∈R
y+5/4y-505=0
We multiply all the terms by the denominator
y*4y-505*4y+5=0
Wy multiply elements
4y^2-2020y+5=0
a = 4; b = -2020; c = +5;
Δ = b2-4ac
Δ = -20202-4·4·5
Δ = 4080320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4080320}=\sqrt{64*63755}=\sqrt{64}*\sqrt{63755}=8\sqrt{63755}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2020)-8\sqrt{63755}}{2*4}=\frac{2020-8\sqrt{63755}}{8} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2020)+8\sqrt{63755}}{2*4}=\frac{2020+8\sqrt{63755}}{8} $
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