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5/4x-12=-1/2x+4
We move all terms to the left:
5/4x-12-(-1/2x+4)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x+4)!=0We get rid of parentheses
x∈R
5/4x+1/2x-4-12=0
We calculate fractions
10x/8x^2+4x/8x^2-4-12=0
We add all the numbers together, and all the variables
10x/8x^2+4x/8x^2-16=0
We multiply all the terms by the denominator
10x+4x-16*8x^2=0
We add all the numbers together, and all the variables
14x-16*8x^2=0
Wy multiply elements
-128x^2+14x=0
a = -128; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·(-128)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*-128}=\frac{-28}{-256} =7/64 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*-128}=\frac{0}{-256} =0 $
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