5/4x+3+7/4x-4=1

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Solution for 5/4x+3+7/4x-4=1 equation: 



5/4x+3+7/4x-4=1

We move all terms to the left:

5/4x+3+7/4x-4-(1)=0



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



We add all the numbers together, and all the variables

5/4x+7/4x-2=0

We multiply all the terms by the denominator


-2*4x+5+7=0

We add all the numbers together, and all the variables

-2*4x+12=0

Wy multiply elements

-8x+12=0

We move all terms containing x to the left, all other terms to the right

-8x=-12

x=-12/-8

x=1+1/2

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