5/4c+12=2

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Solution for 5/4c+12=2 equation:



5/4c+12=2
We move all terms to the left:
5/4c+12-(2)=0
Domain of the equation: 4c!=0
c!=0/4
c!=0
c∈R
We add all the numbers together, and all the variables
5/4c+10=0
We multiply all the terms by the denominator
10*4c+5=0
Wy multiply elements
40c+5=0
We move all terms containing c to the left, all other terms to the right
40c=-5
c=-5/40
c=-1/8

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