5/4*b+7=7/8*b+19b=

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Solution for 5/4*b+7=7/8*b+19b= equation: 



5/4b+7=7/8b+19b=

We move all terms to the left:

5/4b+7-(7/8b+19b)=0



Domain of the equation: 4b!=0

b!=0/4

b!=0

b∈R





Domain of the equation: 8b+19b)!=0

b∈R



We add all the numbers together, and all the variables

5/4b-(+19b+7/8b)+7=0

We get rid of parentheses

5/4b-19b-7/8b+7=0

We calculate fractions


-19b+40b/32b^2+(-28b)/32b^2+7=0

We multiply all the terms by the denominator


-19b*32b^2+40b+(-28b)+7*32b^2=0

We add all the numbers together, and all the variables

40b-19b*32b^2+(-28b)+7*32b^2=0

Wy multiply elements

-608b^3+224b^2+40b+(-28b)=0

We get rid of parentheses

-608b^3+224b^2+40b-28b=0

We do not support ebpression: b^3

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