5/4(40X+10)-16=-3/4(32x-28)

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Solution for 5/4(40X+10)-16=-3/4(32x-28) equation: 



5/4(40X+10)-16=-3/4(32X-28)

We move all terms to the left:

5/4(40X+10)-16-(-3/4(32X-28))=0



Domain of the equation: 4(40X+10)!=0

X∈R





Domain of the equation: 4(32X-28))!=0

X∈R



We calculate fractions


(20X3/(4(40X+10)*4(32X-28)))+(-(-12X4)/(4(40X+10)*4(32X-28)))-16=0



We calculate terms in parentheses: +(20X3/(4(40X+10)*4(32X-28))), so:

20X3/(4(40X+10)*4(32X-28))

We multiply all the terms by the denominator


20X3

We add all the numbers together, and all the variables

20X^3

We do not support eXpression: X^3

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