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5/3y=y-8
We move all terms to the left:
5/3y-(y-8)=0
Domain of the equation: 3y!=0We get rid of parentheses
y!=0/3
y!=0
y∈R
5/3y-y+8=0
We multiply all the terms by the denominator
-y*3y+8*3y+5=0
Wy multiply elements
-3y^2+24y+5=0
a = -3; b = 24; c = +5;
Δ = b2-4ac
Δ = 242-4·(-3)·5
Δ = 636
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{636}=\sqrt{4*159}=\sqrt{4}*\sqrt{159}=2\sqrt{159}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-2\sqrt{159}}{2*-3}=\frac{-24-2\sqrt{159}}{-6} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+2\sqrt{159}}{2*-3}=\frac{-24+2\sqrt{159}}{-6} $
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