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5/3x=2x-7
We move all terms to the left:
5/3x-(2x-7)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
5/3x-2x+7=0
We multiply all the terms by the denominator
-2x*3x+7*3x+5=0
Wy multiply elements
-6x^2+21x+5=0
a = -6; b = 21; c = +5;
Δ = b2-4ac
Δ = 212-4·(-6)·5
Δ = 561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{561}}{2*-6}=\frac{-21-\sqrt{561}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{561}}{2*-6}=\frac{-21+\sqrt{561}}{-12} $
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