5/3x-2=4/x-3

Solution for 5/3x-2=4/x-3 equation:

5/3x-2=4/x-3

We move all terms to the left:

5/3x-2-(4/x-3)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: x-3)!=0

x∈R


We get rid of parentheses

5/3x-4/x+3-2=0

We calculate fractions


5x/3x^2+(-12x)/3x^2+3-2=0

We add all the numbers together, and all the variables

5x/3x^2+(-12x)/3x^2+1=0

We multiply all the terms by the denominator


5x+(-12x)+1*3x^2=0

Wy multiply elements

3x^2+5x+(-12x)=0

We get rid of parentheses

3x^2+5x-12x=0

We add all the numbers together, and all the variables

3x^2-7x=0

a = 3; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·3·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*3}=\frac{0}{6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*3}=\frac{14}{6}
=2+1/3
$