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5/3x+1=-1+5x
We move all terms to the left:
5/3x+1-(-1+5x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
5/3x-(5x-1)+1=0
We get rid of parentheses
5/3x-5x+1+1=0
We multiply all the terms by the denominator
-5x*3x+1*3x+1*3x+5=0
Wy multiply elements
-15x^2+3x+3x+5=0
We add all the numbers together, and all the variables
-15x^2+6x+5=0
a = -15; b = 6; c = +5;
Δ = b2-4ac
Δ = 62-4·(-15)·5
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-4\sqrt{21}}{2*-15}=\frac{-6-4\sqrt{21}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+4\sqrt{21}}{2*-15}=\frac{-6+4\sqrt{21}}{-30} $
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