5/3x+1/3x=x

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Solution for 5/3x+1/3x=x equation:



5/3x+1/3x=x
We move all terms to the left:
5/3x+1/3x-(x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
-1x+5/3x+1/3x=0
We multiply all the terms by the denominator
-1x*3x+5+1=0
We add all the numbers together, and all the variables
-1x*3x+6=0
Wy multiply elements
-3x^2+6=0
a = -3; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·(-3)·6
Δ = 72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{72}=\sqrt{36*2}=\sqrt{36}*\sqrt{2}=6\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{2}}{2*-3}=\frac{0-6\sqrt{2}}{-6} =-\frac{6\sqrt{2}}{-6} =-\frac{\sqrt{2}}{-1} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{2}}{2*-3}=\frac{0+6\sqrt{2}}{-6} =\frac{6\sqrt{2}}{-6} =\frac{\sqrt{2}}{-1} $

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