5/3c+12=2

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Solution for 5/3c+12=2 equation: 



5/3c+12=2

We move all terms to the left:

5/3c+12-(2)=0



Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R



We add all the numbers together, and all the variables

5/3c+10=0

We multiply all the terms by the denominator


10*3c+5=0

Wy multiply elements

30c+5=0

We move all terms containing c to the left, all other terms to the right

30c=-5

c=-5/30

c=-1/6

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