5/3=(q+74)/q

Solution for 5/3=(q+74)/q equation:

5/3=(q+74)/q

We move all terms to the left:

5/3-((q+74)/q)=0


Domain of the equation: q)!=0

q!=0/1

q!=0

q∈R


We calculate fractions


(-((q+74)*3)/q*3)+5q/q*3)=0


We calculate terms in parentheses: +(-((q+74)*3)/q*3), so:

-((q+74)*3)/q*3

We multiply all the terms by the denominator


-((q+74)*3)


We calculate terms in parentheses: -((q+74)*3), so:

(q+74)*3

We multiply parentheses

3q+222

Back to the equation:

-(3q+222)


We get rid of parentheses

-3q-222

Back to the equation:

+(-3q-222)


We get rid of parentheses

-3q+5q/q*3)-222=0

We multiply all the terms by the denominator


-3q*q*3)-222+5q=0

Wy multiply elements

-9q^3*3=0

We do not support eqpression: q^3