5/3-19/3a=3/a

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Solution for 5/3-19/3a=3/a equation: 


D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

5/3-((19/3)*a) = 3/a // - 3/a

5/3-((19/3)*a)-(3/a) = 0

(-19/3)*a-3*a^-1+5/3 = 0

5/3*a^0-19/3*a^1-3*a^-1 = 0

(5/3*a^1-19/3*a^2-3*a^0)/(a^1) = 0 // * a^2

a^1*(5/3*a^1-19/3*a^2-3*a^0) = 0

a^1

(-19/3)*a^2+(5/3)*a-3 = 0

(-19/3)*a^2+(5/3)*a-3 = 0

DELTA = (5/3)^2-(-3*4*(-19/3))

DELTA = -659/9

DELTA < 0

a in { } 

a belongs to the empty set

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