5/3(t-1)=4/5(2t+1)+2/3

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Solution for 5/3(t-1)=4/5(2t+1)+2/3 equation: 


t in (-oo:+oo)

(5/3)*(t-1) = (4/5)*(2*t+1)+2/3 // - (4/5)*(2*t+1)+2/3

(5/3)*(t-1)-((4/5)*(2*t+1))-(2/3) = 0

(5/3)*(t-1)+(-4/5)*(2*t+1)-2/3 = 0

5/3*(t-1)-4/5*(2*t+1)-2/3 = 0

(5/3*3*(t-1))/3+(-4/5*3*(2*t+1))/3-2/3 = 0

5/3*3*(t-1)-4/5*3*(2*t+1)-2 = 0

1/5*t-37/5-2 = 0

1/5*t-47/5 = 0

(1/5*t-47/5)/3 = 0

(1/5*t-47/5)/3 = 0 // * 3

1/5*t-47/5 = 0

1/5*t-47/5 = 0 // + 47/5

1/5*t = 47/5 // : 1/5

t = 47/5/1/5

t = 47

t = 47

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