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5/3(6x-8)=1/3(9x-12)
We move all terms to the left:
5/3(6x-8)-(1/3(9x-12))=0
Domain of the equation: 3(6x-8)!=0
x∈R
Domain of the equation: 3(9x-12))!=0We calculate fractions
x∈R
(15x9/(3(6x-8)*3(9x-12)))+(-3x6/(3(6x-8)*3(9x-12)))=0
We calculate terms in parentheses: +(15x9/(3(6x-8)*3(9x-12))), so:
15x9/(3(6x-8)*3(9x-12))
We multiply all the terms by the denominator
15x9
We add all the numbers together, and all the variables
15x^9
We do not support expression: x^9
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