5/3(3c-3)=1/5(20c+5)

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Solution for 5/3(3c-3)=1/5(20c+5) equation: 



5/3(3c-3)=1/5(20c+5)

We move all terms to the left:

5/3(3c-3)-(1/5(20c+5))=0



Domain of the equation: 3(3c-3)!=0

c∈R





Domain of the equation: 5(20c+5))!=0

c∈R



We calculate fractions


(25c2/(3(3c-3)*5(20c+5)))+(-3c3/(3(3c-3)*5(20c+5)))=0



We calculate terms in parentheses: +(25c2/(3(3c-3)*5(20c+5))), so:

25c2/(3(3c-3)*5(20c+5))

We multiply all the terms by the denominator


25c2

We add all the numbers together, and all the variables

25c^2

Back to the equation:

+(25c^2)





We calculate terms in parentheses: +(-3c3/(3(3c-3)*5(20c+5))), so:

-3c3/(3(3c-3)*5(20c+5))

We multiply all the terms by the denominator


-3c3

We add all the numbers together, and all the variables

-3c^3

We do not support ecpression: c^3

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