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5/2y+4=2y-1
We move all terms to the left:
5/2y+4-(2y-1)=0
Domain of the equation: 2y!=0We get rid of parentheses
y!=0/2
y!=0
y∈R
5/2y-2y+1+4=0
We multiply all the terms by the denominator
-2y*2y+1*2y+4*2y+5=0
Wy multiply elements
-4y^2+2y+8y+5=0
We add all the numbers together, and all the variables
-4y^2+10y+5=0
a = -4; b = 10; c = +5;
Δ = b2-4ac
Δ = 102-4·(-4)·5
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-6\sqrt{5}}{2*-4}=\frac{-10-6\sqrt{5}}{-8} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+6\sqrt{5}}{2*-4}=\frac{-10+6\sqrt{5}}{-8} $
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