5/2x-2=9/2x-2(x+1)

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Solution for 5/2x-2=9/2x-2(x+1) equation: 


x in (-oo:+oo)

(5/2)*x-2 = (9/2)*x-(2*(x+1)) // - (9/2)*x-(2*(x+1))

2*(x+1)+(5/2)*x-((9/2)*x)-2 = 0

2*(x+1)+(5/2)*x+(-9/2)*x-2 = 0

2*(x+1)+(5*x)/2+(-9*x)/2-2 = 0

(2^2*(x+1))/2+(5*x)/2+(-9*x)/2+(-2*2)/2 = 0

2^2*(x+1)+5*x-9*x-2*2 = 0

9*x-9*x-4+4 = 0

4-4 = 0

0 = 0

0/2 = 0

0/2 = 0 // * 2

0 = 0

x belongs to the empty set

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