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5/2x+3=6x+4
We move all terms to the left:
5/2x+3-(6x+4)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
5/2x-6x-4+3=0
We multiply all the terms by the denominator
-6x*2x-4*2x+3*2x+5=0
Wy multiply elements
-12x^2-8x+6x+5=0
We add all the numbers together, and all the variables
-12x^2-2x+5=0
a = -12; b = -2; c = +5;
Δ = b2-4ac
Δ = -22-4·(-12)·5
Δ = 244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{244}=\sqrt{4*61}=\sqrt{4}*\sqrt{61}=2\sqrt{61}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{61}}{2*-12}=\frac{2-2\sqrt{61}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{61}}{2*-12}=\frac{2+2\sqrt{61}}{-24} $
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