5/2=2/(x+3)-2

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Solution for 5/2=2/(x+3)-2 equation: 



5/2=2/(x+3)-2

We move all terms to the left:

5/2-(2/(x+3)-2)=0



Domain of the equation: (x+3)-2)!=0

x∈R



We calculate fractions


()/(x+3)+(5x+15)/(x+3)=0

We multiply all the terms by the denominator


(5x+15)+()=0

We add all the numbers together, and all the variables

(5x+15)=0

We get rid of parentheses

5x+15=0

We move all terms containing x to the left, all other terms to the right

5x=-15

x=-15/5

x=-3

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