5/2(3x-2)=4/5(x-4)

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Solution for 5/2(3x-2)=4/5(x-4) equation: 



5/2(3x-2)=4/5(x-4)

We move all terms to the left:

5/2(3x-2)-(4/5(x-4))=0



Domain of the equation: 2(3x-2)!=0

x∈R





Domain of the equation: 5(x-4))!=0

x∈R



We calculate fractions


(25xx/(2(3x-2)*5(x-4)))+(-8x3/(2(3x-2)*5(x-4)))=0



We calculate terms in parentheses: +(25xx/(2(3x-2)*5(x-4))), so:

25xx/(2(3x-2)*5(x-4))

We multiply all the terms by the denominator


25xx

Back to the equation:

+(25xx)





We calculate terms in parentheses: +(-8x3/(2(3x-2)*5(x-4))), so:

-8x3/(2(3x-2)*5(x-4))

We multiply all the terms by the denominator


-8x3

We add all the numbers together, and all the variables

-8x^3

We do not support expression: x^3

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