5/2(2x+18)=1/5(25x+30)

Solution for 5/2(2x+18)=1/5(25x+30) equation:

5/2(2x+18)=1/5(25x+30)

We move all terms to the left:

5/2(2x+18)-(1/5(25x+30))=0


Domain of the equation: 2(2x+18)!=0

x∈R



Domain of the equation: 5(25x+30))!=0

x∈R


We calculate fractions


(25x2/(2(2x+18)*5(25x+30)))+(-2x2/(2(2x+18)*5(25x+30)))=0


We calculate terms in parentheses: +(25x2/(2(2x+18)*5(25x+30))), so:

25x2/(2(2x+18)*5(25x+30))

We multiply all the terms by the denominator


25x2

We add all the numbers together, and all the variables

25x^2

Back to the equation:

+(25x^2)



We calculate terms in parentheses: +(-2x2/(2(2x+18)*5(25x+30))), so:

-2x2/(2(2x+18)*5(25x+30))

We multiply all the terms by the denominator


-2x2

We add all the numbers together, and all the variables

-2x^2

Back to the equation:

+(-2x^2)


We add all the numbers together, and all the variables

25x^2+(-2x^2)=0

We get rid of parentheses

25x^2-2x^2=0

We add all the numbers together, and all the variables

23x^2=0

a = 23; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·23·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{46}=0$