5/2(2-k)=2(3k-1)-2/3k

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Solution for 5/2(2-k)=2(3k-1)-2/3k equation: 



5/2(2-k)=2(3k-1)-2/3k

We move all terms to the left:

5/2(2-k)-(2(3k-1)-2/3k)=0



Domain of the equation: 2(2-k)!=0

k∈R





Domain of the equation: 3k)!=0

k!=0/1

k!=0

k∈R



We add all the numbers together, and all the variables

5/2(-1k+2)-(2(3k-1)-2/3k)=0

We calculate fractions


15k/(12k^2-2k)+(-(6k-4k0)/(12k^2-2k)=0



We calculate terms in parentheses: +(-(6k-4k0)/(12k^2-2k), so:

-(6k-4k0)/(12k^2-2k

We add all the numbers together, and all the variables

-(+2k)/(12k^2-2k

We multiply all the terms by the denominator


-(+2k)

We get rid of parentheses

-2k

Back to the equation:

+(-2k)



We get rid of parentheses

15k/(12k^2-2k)-2k=0

We multiply all the terms by the denominator


15k-2k*(12k^2-2k)=0

We multiply parentheses

-24k^3+4k^2+15k=0

We do not support ekpression: k^3

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