5/2(10x+4)=20

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Solution for 5/2(10x+4)=20 equation:



5/2(10x+4)=20
We move all terms to the left:
5/2(10x+4)-(20)=0
Domain of the equation: 2(10x+4)!=0
x∈R
We multiply all the terms by the denominator
-20*2(10x+4)+5=0
Wy multiply elements
-40x(1+5=0

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