5/(x-2)=(-3/(x+7))+37/(x-2)(x+7)

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Solution for 5/(x-2)=(-3/(x+7))+37/(x-2)(x+7) equation: 


D( x )

x+7 = 0

x-2 = 0

x+7 = 0

x+7 = 0

x+7 = 0 // - 7

x = -7

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:-7) U (-7:2) U (2:+oo)

5/(x-2) = (37/(x-2))*(x+7)-3/(x+7) // - (37/(x-2))*(x+7)-3/(x+7)

5/(x-2)-(-3/(x+7))-((37/(x-2))*(x+7)) = 0

5/(x-2)+3*(x+7)^-1-37*(x-2)^-1*(x+7) = 0

5/(x-2)+3/(x+7)+(-37*(x+7))/(x-2) = 0

(5*(x+7))/((x-2)*(x+7))+(3*(x-2))/((x-2)*(x+7))+(-37*(x+7)^2)/((x-2)*(x+7)) = 0

5*(x+7)+3*(x-2)-37*(x+7)^2 = 0

8*x-37*x^2-518*x-1813+29 = 0

-37*x^2-510*x-1784 = 0

-37*x^2-510*x-1784 = 0

-1*(37*x^2+510*x+1784) = 0

37*x^2+510*x+1784 = 0

DELTA = 510^2-(4*37*1784)

DELTA = -3932

DELTA < 0

-1 = 0

-1/((x-2)*(x+7)) = 0

-1/((x-2)*(x+7)) = 0 // * (x-2)*(x+7)

-1 = 0

x belongs to the empty set

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