5/(x+5)=3/(2x-4)

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Solution for 5/(x+5)=3/(2x-4) equation: 



5/(x+5)=3/(2x-4)

We move all terms to the left:

5/(x+5)-(3/(2x-4))=0



Domain of the equation: (x+5)!=0

We move all terms containing x to the left, all other terms to the right

x!=-5

x∈R





Domain of the equation: (2x-4))!=0

x∈R



We calculate fractions


10x/((x+5)*(2x-4)))+(-(3*(x+5))/((x+5)*(2x-4)))=0



We calculate terms in parentheses: -(3*(x+5))/((x+5)*(2x-4))), so:

3*(x+5))/((x+5)*(2x-4))

We multiply all the terms by the denominator


3*(x+5))

We multiply parentheses

3x+

We add all the numbers together, and all the variables

3x

Back to the equation:

-(3x)



We add all the numbers together, and all the variables

-3x+10x/((x+5)*(2x-4)))+(=0

We multiply all the terms by the denominator


-3x*((x+5)*(2x-4)))+(+10x=0

We add all the numbers together, and all the variables

10x-3x*((x+5)*(2x-4)))+(=0

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