5/(x+2)+4/(x+1)=2

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Solution for 5/(x+2)+4/(x+1)=2 equation: 


D( x )

x+2 = 0

x+1 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-2) U (-2:-1) U (-1:+oo)

5/(x+2)+4/(x+1) = 2 // - 2

5/(x+2)+4/(x+1)-2 = 0

(5*(x+1))/((x+2)*(x+1))+(4*(x+2))/((x+2)*(x+1))+(-2*(x+2)*(x+1))/((x+2)*(x+1)) = 0

5*(x+1)+4*(x+2)-2*(x+2)*(x+1) = 0

9*x-2*x^2-6*x-4+13 = 0

3*x-2*x^2+9 = 0

3*x-2*x^2+9 = 0

3*x-2*x^2+9 = 0

DELTA = 3^2-(-2*4*9)

DELTA = 81

DELTA > 0

x = (81^(1/2)-3)/(-2*2) or x = (-81^(1/2)-3)/(-2*2)

x = -3/2 or x = 3

(x+3/2)*(x-3) = 0

((x+3/2)*(x-3))/((x+2)*(x+1)) = 0

((x+3/2)*(x-3))/((x+2)*(x+1)) = 0 // * (x+2)*(x+1)

(x+3/2)*(x-3) = 0

( x+3/2 )

x+3/2 = 0 // - 3/2

x = -3/2

( x-3 )

x-3 = 0 // + 3

x = 3

x in { -3/2, 3 }

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