5/(x+1)-(5/2)=6/(3x+3)

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Solution for 5/(x+1)-(5/2)=6/(3x+3) equation: 



5/(x+1)-(5/2)=6/(3x+3)

We move all terms to the left:

5/(x+1)-(5/2)-(6/(3x+3))=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R





Domain of the equation: (3x+3))!=0

x∈R



We add all the numbers together, and all the variables

5/(x+1)-(6/(3x+3))-(+5/2)=0

We get rid of parentheses

5/(x+1)-(6/(3x+3))-5/2=0

We calculate fractions


30x/((x+1)*(3x+3))*2)+(-(6*(x+1)*2)/((x+1)*(3x+3))*2)+(-5*(x+1)*(3x+3)))/((x+1)*(3x+3))*2)=0

We add all the numbers together, and all the variables

30x/((x+1)*(3x+3))*2)+(-(6*(x+1)*2)/((x+1)*(3x+3))*2)+(-5*(x+1)*(3x+3)))/((x+1)*(3x=0

We calculate fractions


1)*(3x+(30x-(6*(x+1)*2)*(x/(((x+1)*(3x+3))*2)+(*(x+(-5*(x+1)*(3x+3)))*((x+1)*3x/(((x+1)*(3x+3))*2)+(*(x=0

We can not solve this equation

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