5/(s-2)(s-3)(s-6)

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Solution for 5/(s-2)(s-3)(s-6) equation: 


D( s )

s-2 = 0

s-2 = 0

s-2 = 0

s-2 = 0 // + 2

s = 2

s in (-oo:2) U (2:+oo)

(5/(s-2))*(s-3)*(s-6) = 0

(5*(s-3)*(s-6))/(s-2) = 0

( 5 )

5 = 0

s belongs to the empty set

( s-3 )

s-3 = 0 // + 3

s = 3

( s-6 )

s-6 = 0 // + 6

s = 6

s in { 3, 6 }

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