5/(p+1)=12/(p+1)

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Solution for 5/(p+1)=12/(p+1) equation: 


D( p )

p+1 = 0

p+1 = 0

p+1 = 0

p+1 = 0 // - 1

p = -1

p in (-oo:-1) U (-1:+oo)

5/(p+1) = 12/(p+1) // - 12/(p+1)

5/(p+1)-(12/(p+1)) = 0

5/(p+1)-12*(p+1)^-1 = 0

5/(p+1)-12/(p+1) = 0

5-12 = 0

-7 = 0

-7/(p+1) = 0

-7/(p+1) = 0 // * p+1

-7 = 0

p belongs to the empty set

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