5/(4x)+1/x-x=0

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Solution for 5/(4x)+1/x-x=0 equation: 


D( x )

x = 0

4*x = 0

x = 0

x = 0

4*x = 0

4*x = 0

4*x = 0 // : 4

x = 0

x in (-oo:0) U (0:+oo)

5/(4*x)-x+1/x = 0

9/4*x^-1-1*x^1 = 0

(9/4*x^0-1*x^2)/(x^1) = 0 // * x^2

x^1*(9/4*x^0-1*x^2) = 0

x^1

9/4-x^2 = 0

9/4-x^2 = 0

DELTA = 0^2-(-1*4*(9/4))

DELTA = 9

DELTA > 0

x = (9^(1/2)+0)/(-1*2) or x = (0-9^(1/2))/(-1*2)

x = -3/2 or x = 3/2

x in { -3/2, 3/2} 

x in { -3/2, 3/2 }

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