5/(40-k)=3/k

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Solution for 5/(40-k)=3/k equation: 


D( k )

40-k = 0

k = 0

40-k = 0

40-k = 0

40-k = 0 // - 40

-k = -40 // * -1

k = 40

k = 0

k = 0

k in (-oo:0) U (0:40) U (40:+oo)

5/(40-k) = 3/k // - 3/k

5/(40-k)-(3/k) = 0

5/(40-k)-3*k^-1 = 0

5/(40-k)-3/k = 0

(5*k)/(k*(40-k))+(-3*(40-k))/(k*(40-k)) = 0

5*k-3*(40-k) = 0

8*k-120 = 0

(8*k-120)/(k*(40-k)) = 0

(8*k-120)/(k*(40-k)) = 0 // * k*(40-k)

8*k-120 = 0

8*k-120 = 0 // + 120

8*k = 120 // : 8

k = 120/8

k = 15

k = 15

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